Question

resuelveeeeeeeeeeeeee

Answer 1

$\frac{ 27 {x}^{3}. {x}^{2}. {y}^{2} . {y}^{4} }{9 {x}^{2} {y}^{4} } \\ \frac{27(4). {x}^{2} {y}^{4} }{9 {x}^{2} {y}^{4} } \\ = 12$