Question

logx (3x+40)=2




Ayuda ​

Answer 1

Respuesta:

$3x + 40 = {x}^{2} \\ 3x + 40 - {x}^{2} = 0 \\ - {x}^{2} + 3x + 40 = 0 \\ {x}^{2} - 3x - 40 = 0 \\ {x}^{2} + 5x - 8x - 40 = 0 \\ x(x + 5) - 8(x + 5) = 0 \\ (x + 5) \times (x - 8) = 0 \\ x + 5 = 0 \\ x - 8 = 0 \\ x = - 5 \: ecuacion \: 1 \\ x = 8 \\ ecuacion2$

x=8