Question

Determinar el numero de moles de soluto presentes en 455 ml. De una disolución de HCl 3.75 molar

Answer 1

Mm HCl = 36.45 g/mol

M = MOL SOLUTO / V(L)

V = 455 / 1000 = 0.455 L

mol soluto = M x V(L)

mol = 3.75 mol/L  x  0.455 L

mol = 1.7063

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mol = 455 mL  x    1 L       x  3.75 mol
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                         1000 mL          1 L

mol = 1.7063