Question

recurrencia lineal con coeficientes constantes 4an– 7an-1 + 2an-2 = n2 + 3.

Answer 1

4an– 7an-1 + 2an-2 = n2 + 3
4an - 7an + 2an - n^2 - 1 - 2 - 3
- an - n^2 - 6= 0
n^2 + an + 6 = 0
(n + 3) ( n + 2 )
(n + 6) ( n + 1)
posibles resultados