Question

1-senX/secX=cos^3X/1+senX

Answer 1

$\frac{1-senx}{secx} = \frac{ cos^{3}x }{1+senx}$

$cosx(1-senx) = \frac{ cos^{3}x }{1+senx}$

$\frac{ cos^{2}x }{(1+senx)(1-senx)} = 1$

$\frac{ cos^{2}x }{1- sen^{2}x } = 1 [tex] \frac{ cos^{2}x }{ cos^{2}x } = 1$

$1 = 1$