Question

Cuales son las fraciones molares de metanol(CH3OH) y agua en una disolucion que contiene 40,0g de CH3OH y 54,0g de H20

Answer 1

Mm H2O = 18 g/mol
   CH3OH = 32 g/mol

n   =  masa /Mm

n1 sto = 40 g / 32 g /mol = 1.25 mol

n2svte = 54 g/ 18 g/mol = 3 mol

n1 + n2 (sto + svte) = 1.25 mol + 3 mol = 4.25 mol

Xsto =     n1
           ````````````
           n1 + n2

Xsto = 1.25 mol
           ````````````
            4.25 mol

Xsto = 0.294

Xsvte  =     n2
              ````````````
               n1  +  n2

Xste =     3  mol
          ````````````````
             4.25 mol

Xste = 0.704