Question

por favor ayudenme
b^{2} +10b+11=0

Answer 1

Respuesta:

x₁ = -6.33

x₂ = -13.67

Explicación paso a paso:

b²+10b+11 = 0

a = 1   b = 10   c = 11

$x = -b +\frac{\sqrt{b^{2} -4ac} }{2a} = -10 +\frac{\sqrt{10^{2} -4(1)(11)c} }{2(1)} = -10 +\frac{\sqrt{100 -44} }{2} = -10 +\frac{\sqrt{54} }{2} \\x = -10 +\frac{7.35}{2}$

x = -10±3.67

x₁ = -10+3.67 = -6.33

x₂ = -10-3.67 = -13.67