Question

(2a²- b³)³porfavor
AYUDAAAAA ​

Answer 1

RESOLVER:

$\left(2a^2-b^3\right)^3$

Aplicamos la fórmula del binomio al cubo: $\left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3$

$\left(2a^2-b^3\right)^3=\left(2a^2\right)^3-3\left(2a^2\right)^2b^3+3\cdot \:2a^2\left(b^3\right)^2-\left(b^3\right)^3$

$=\left(2a^2\right)^3-3\left(2a^2\right)^2b^3+3\cdot \:2a^2\left(b^3\right)^2-\left(b^3\right)^3$

Simplificamos $\left(2a^2\right)^3-3\left(2a^2\right)^2b^3+3\cdot \:2a^2\left(b^3\right)^2-\left(b^3\right)^3: 8a^6-12a^4b^3+6a^2b^6-b^9$

$\boxed{=8a^6-12a^4b^3+6a^2b^6-b^9}$

$Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)$