Question

(X+1) al cubo -(x-1) al cubo = 6x(x-3)

Answer 1

$(x+1)^{3} -(x-1) ^{3} =6x(x-3) \\ \\ \\ x^{3}+3x^{2}+3x+1-(x^{3}-3x^{2}+3x-1)= 6 x^{2}-3x \\ \\ \\ x^{3}+3x^{2}+3x+1-x^{3}+3x^{2}-3x+1= 6 x^{2}-3x \\ \\ \\ 6x^{2}+2= 6 x^{2}-3x \\ \\ \\ 2= -3x \\ \\ \boxed{ -\dfrac{2}{3}=x }$


Espero que te sirva, salu2!!!!