Question

Resta P(z) = 2z5 – 9z3 + 10z + 8 de la suma de Q(z) = 4z6 – 7z +4 + 2z3 + 6
con R(z) = 2z6 – 3z5 + 7z2 – 4z + 5

Los numeros a la derecha son el exponente de la potencia

Answer 1

Respuesta:

Q(z)=4z6-7z+4+2z3+6

Q'(z)=d/dz (4z*6-7z+4+2z*3+6)

Q'(z)=d/dz (24z-7z+4+6z+6)

Q'(z)=d/dz (23z+10)

Q'(z)=d/dz (23z)+ d/dz (10)

Q'(z)=23+0

Q'(z)=23

R(z)=2z6-3z5+7z2-4z+5

r'(z)=d/dz (2z*6-3z*5+7z*2-4z+5)

r'(z)=d/dz (12z-15z+14z-4z+5)

r'(z)=d/dz (7z+5)

r'(z)=d/dz (7z)+d/dz (5)

r'(z)= 7+0

r'(z)=7

23+7=30

P(z)=2z5-9z3+10z+8

P'(z)=d/dz (2z*5-9z*3+10z+8)

P'(z)=d/dz (10z-27z+10z+8)

P'(z)=d/dz (-7z+8)

P'(z)=d/dz (-7z)+ d/dz (8)

P'(z)=d/dz -7+0

P'(z)= -7

30-(-7)=37

espero te ayude