Question

Alguien que me resuelva este problema: 3(x+2)(x+3)=60

Answer 1

3(x+2)(x+3) = 60
3((x*x) +(3x) +(2x) +(2*3)) = 60
3(x² + 5x + 6) = 60
3x² + 15x + 18 = 60
3x² + 15x + 18 - 60 = 0
3x² + 15x - 42 = 0

x = {-15+-√(15²-(4*3*-42))} / 2*3
x = {-15+-√(225 + 504)} / 6
x = {-15+-√729}/6
x = {-15+-27} / 6

x₁ = {-15-27}/6 = -42/6 = -7
x₂ = {-15+27}/6 = 12/6 = 2

Respuestas:
x₁ = -7
x₂ = 2


Saludos..........