Question

División de polinomios
(3x⁴+x³+5x²+x-5): (x²-3x+1) ayudaa​

Answer 1

Respuesta:

$3x^2+10x+32+\frac{87x-37}{x^2-3x+1}$

Explicación paso a paso:

$\frac{\left(3x^4+x^3+5x^2+x-5\right)}{\left(x^2-3x+1\right)}\\\\\frac{3x^4+x^3+5x^2+x-5}{x^2-3x+1}=3x^2+\frac{10x^3+2x^2+x-5}{x^2-3x+1}\\\\=3x^2+\frac{10x^3+2x^2+x-5}{x^2-3x+1}\\\\\frac{10x^3+2x^2+x-5}{x^2-3x+1}=10x+\frac{32x^2-9x-5}{x^2-3x+1}\\\\=3x^2+10x+\frac{32x^2-9x-5}{x^2-3x+1}\\\\\frac{32x^2-9x-5}{x^2-3x+1}=32+\frac{87x-37}{x^2-3x+1}\\\\=3x^2+10x+32+\frac{87x-37}{x^2-3x+1}$