Question

5²−10²+4×(7²−9×2)−11²
ayuda plis​

Answer 1

ΗΘΙΑ

procedimiento :

5²−10²+4×(7²−9×2)−11²

$=5^{2} -10^{2} +4x31-11^{2}$

$=25-10^{2} +4x31-11^{2}$

$=25-100+4x31-11^{2}$

$=25-100+4x31-121$

$=25-100+124-121$

$=-72$

salu2!!