Question

1)
Si: A = (–8) (+2) – 3


B = (+4) (–2) + 4


C =(50) ÷ (–2) – 6


Hallar:





A + B + C

5)
Si: A = (–8) (+2) – 3


B = (+4) (–2) + 4


C =(50) ÷ (–2) – 6





Hallar : 2B – 3A

Answer 1

Respuesta:

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