Question

cacular el valor x
x+tg 53º=sec53º

Answer 1

$x + \tan(53) = \sec(53) \\ \\ x + \frac{ \sin(53) }{ \cos(53) } = \frac{1}{ \cos(53 ) } \\ x = \frac{1 - \sin(53) }{ \cos(53) } \\ x = 0.33459531$