Question

Si: $\frac{a}{6}$=b/3=c/4=k ; donde a+b-c=35,hallar a+b

Answer 1

Solución:

Tenemos:  a / 6 = b / 3 = c / 4 = k
a = 6k
b = 3k
c = 4k

a + b - c = 35

6k + 3k - 4k = 35
5k = 35
k = 7

a = 6k = 6(7) = 42
b = 3k = 3(7) = 21

a + b = 63