Question

Si: 8/a = 12/b = 16/c;donde a+b+c=45 hallar "a"

Answer 1

sol
8/a = 12/b, entonces   b = 12a/8 = (3a)/4

8/a = 16/c, entonces  c  = 16a/8 = 2a

a+b+c = 45
a + (3a)/4 +2a = 45
         3a +3a/4 = 45
            (15/4)a = 45
                        a = 180/15
                         a = 12  

b = (3a)/4 = 3*12/4 = 9
c = 2a =2*12 = 24

prueba
a+b+c = 45
12+24+9 = 45
           45 = 45