Question

( TENIENDO EN CUENTA QUE XES LA VARIABLE EN TODOS LOS CASOS HALLAR LOS VALORES DE LA MISMA:​

Answer 1

Hola

Respuestas

1.  no me sale

2. x = 1

3. x = -3

4.x = 1

Espero haberte ayudado ✌

Answer 2

Explicación paso a paso:

1.

$log_{4}( \sqrt[3]{64} ) = \\ {4}^{x} = \sqrt[3]{64} \\ {4}^{x} = {4}^{1} \\ x = 1$

2.

${16}^{3(x) - 3} = {128}^{x - 1} \\ {2}^{4(3x - 3)} = {2}^{7(x - 1)} \\ {2}^{12x - 12} = {2}^{7x - 7} \\ 12x - 12 = 7x - 7 \\ 12x - 7x = 12 - 7 \\ 5x = 5 \\ x = 1$

3.

${2}^{x} = {8}^{x + 2} \\ {2}^{x} = {2}^{3x + 6} \\ x = 3x + 2 \\ - 6 = 2x \\ - 3 = x$

4.

${e}^{2x - 2} = 1 \\ 2x - 2 = 0 \\ 2x = 2 \\ x = 1$

Answer 3

Explicación paso a paso:

1.

$log_{4}( \sqrt[3]{64} ) = \\ {4}^{x} = \sqrt[3]{64} \\ {4}^{x} = {4}^{1} \\ x = 1$

2.

${16}^{3(x) - 3} = {128}^{x - 1} \\ {2}^{4(3x - 3)} = {2}^{7(x - 1)} \\ {2}^{12x - 12} = {2}^{7x - 7} \\ 12x - 12 = 7x - 7 \\ 12x - 7x = 12 - 7 \\ 5x = 5 \\ x = 1$

3.

${2}^{x} = {8}^{x + 2} \\ {2}^{x} = {2}^{3x + 6} \\ x = 3x + 2 \\ - 6 = 2x \\ - 3 = x$

4.

${e}^{2x - 2} = 1 \\ 2x - 2 = 0 \\ 2x = 2 \\ x = 1$