Question

√400÷√25+9÷⁴√81+5²-25+12​

Answer 1

RESOLVER:

$\frac{\sqrt{400}}{\sqrt{25}}+\frac{9}{\sqrt[4]{81}}+5^2-25+12$

Cancelamos

$\frac{\sqrt{400}}{\sqrt{25}}:2^{2}$

$=2^2+\frac{9}{\sqrt[4]{81}}+5^2-25+12$

Cancelamos

$\frac{9}{\sqrt[4]{81}}:3$

$=2^2+3+5^2-25+12$

$3-25+12=-10$

$=2^2+5^2-10$

$2^2=4$

$5^2=25$

$=4+25-10$

$4+25-10=19$

$=19$

$Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)$