1. Un avión despega cuando su velocidad es 306 Km/h. si los alcanza en 170 s partiendo del reposo. a. Que distancia de la pista ha recorrido cuando el cronometro marca 10, 20, 30, 40, 50 y 60 segundos.
Respuestas
Respuesta dada por:
0
Velocidad de despegue = 306 Km/h
306 Km/h x (1000 m/ 1 Km)x( 1 hora/3600 seg) = 85 m/s
Velocidad final (Vf) = 85 m/s
Velocidad Inicial (Vi) = 0 m/s
t = 170 segundos
Vf = Vi + at
Vf = 85 m/s; Vi = 0 m/s; t = 170 seg
85 m/s = 0 + at
a = (85 m/s)/(170 s) = 0.5 m/s²
d = (Vi)(t) +(0.5)(a)(t²)
d = (0.5)(0.5 m/s²)(t²)
Para t = 10 seg
d = (0.5)(0.5 m/s²)(10 seg)²
d = (0.5)(0.5 m/s²)(100 seg²) = 25 m
d = 25 m
Para t = 20.
d = (0.5)(0.5 m/s²)(20 seg)²
d = (0.5)(0.5 m/s²)(400 seg²)
d = 100 m
Para t = 30 seg
d = (0.5)(0.5 m/s²)(30 seg)²
d = (0.5)(0.5 m/s²)(900 seg²)
d = 225 m
Para t = 40 seg
d = (0.5)(0.5 m/s²)(40 seg)²
d = (0.5)(0.5 m/s²)(1600 seg²)
d = 400 m
Para t = 50 seg
d = (0.5)(0.5 m/s²)(50 seg)²
d = (0.5)(0.5 m/s²)(2500 seg²)
d = 625 m
Para t = 60 seg
d = (0.5)(0.5 m/s²)(60 seg)²
d = (0.5)(0.5 m/s²)(3600 seg²)
d = 900 m
306 Km/h x (1000 m/ 1 Km)x( 1 hora/3600 seg) = 85 m/s
Velocidad final (Vf) = 85 m/s
Velocidad Inicial (Vi) = 0 m/s
t = 170 segundos
Vf = Vi + at
Vf = 85 m/s; Vi = 0 m/s; t = 170 seg
85 m/s = 0 + at
a = (85 m/s)/(170 s) = 0.5 m/s²
d = (Vi)(t) +(0.5)(a)(t²)
d = (0.5)(0.5 m/s²)(t²)
Para t = 10 seg
d = (0.5)(0.5 m/s²)(10 seg)²
d = (0.5)(0.5 m/s²)(100 seg²) = 25 m
d = 25 m
Para t = 20.
d = (0.5)(0.5 m/s²)(20 seg)²
d = (0.5)(0.5 m/s²)(400 seg²)
d = 100 m
Para t = 30 seg
d = (0.5)(0.5 m/s²)(30 seg)²
d = (0.5)(0.5 m/s²)(900 seg²)
d = 225 m
Para t = 40 seg
d = (0.5)(0.5 m/s²)(40 seg)²
d = (0.5)(0.5 m/s²)(1600 seg²)
d = 400 m
Para t = 50 seg
d = (0.5)(0.5 m/s²)(50 seg)²
d = (0.5)(0.5 m/s²)(2500 seg²)
d = 625 m
Para t = 60 seg
d = (0.5)(0.5 m/s²)(60 seg)²
d = (0.5)(0.5 m/s²)(3600 seg²)
d = 900 m
Preguntas similares
hace 6 años
hace 6 años
hace 9 años
hace 9 años
hace 9 años