Question

factorizar 6m²-13am-15a²​

Answer 1

¡Hello!

Resolvemos:

$\texttt{En general, dado} a{x}^{2}+bx+c, \texttt{la forma factorizada es:} \\ \\ \bf a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a}) \\ \\ \texttt{En este caso}, a=6, b=\−13a y c=-15{a}^{2}. \\ \\ \bf6(m-\frac{13a+\sqrt{{(-13a)}^{2}-4\times 6\times -15{a}^{2}}}{2\times 6})(m-\frac{13a-\sqrt{{(-13a)}^{2}-4\times 6\times -15{a}^{2}}}{2\times 6} \\ \\ \texttt{ Simplifica}. \\ \\ \bf(m-3a) (6m+5a)$

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¡Saludos!