Question

−x2+16x=0
x2−25x=0
−x2+9x=0

solución diferente a 0

Answer 1

Explicación paso a paso:

$- {x}^{2} + 16x = 0 \\ {x}^{2} - 16x = 0 \\ x(x - 16) = 0 \\ x = 0 \: \: \: o \: \: x = 16 \\ x ^{2} - 25x = 0 \\ x(x - 25) = 0 \\ x = 0 \: \: o \: x = 25$

$- {x}^{2} + 9x = 0 \\ {x}^{2} - 9x = 0 \\ x(x - 9) = 0 \\ x = 0 \: \: o \: x = 9$