Question

factorizar 20 m^4n^2 + 28m^3n^3 - 12m^2n
AYUDA chavales

Answer 1

Respuesta:

4mn(20n+21n²-6)

Explicación paso a paso:

Simplifica  20m\times 4{n}^{2}20m×4n2  a  80m{n}^{2}80mn2.

80m{n}^{2}+28m\times 3{n}^{3}-12m\times 2n80mn2+28m×3n3−12m×2n

 

2Simplifica  28m\times 3{n}^{3}28m×3n3  a  84m{n}^{3}84mn3.

80m{n}^{2}+84m{n}^{3}-12m\times 2n80mn2+84mn3−12m×2n

3

 

Simplifica  12m\times 2n12m×2n  a  24mn24mn.

80m{n}^{2}+84m{n}^{3}-24mn80mn2+84mn3−24mn

4

 

Extrae el factor común 4mn4mn.

4mn(20n+21{n}^{2}-6)4mn(20n+21n2−6)