Question

ayudenme por favore che xd

Answer 1

Respuesta:

$I. (3n+2m)^{2}\\ =4m^{2} + 12mn + 9n^{2} \\\\II. (3m+2n) (3m-2n) \\ =9m^{2}-4n^{2}\\III.(3n-2m) (3n+2m)\\ = -4m^{2} +9n^{2} \\\\IV. (3n-2m) (3n+2m)\\ = -4m^{2} + 9n^{2}$