Question

14x²+22x-12÷(7x-3)
aiuda

Answer 1

Respuesta:

$14x^2+22x-12\div \left(7x-3\right)$

$\mathrm{Resolvemos:}$

$14x^2+22x-12=2\left(7x^2+11x-6\right)$

$\frac{2\left(7x^2+11x-6\right)}{7x-3}$

$\mathrm{Factorizar:}$

$7x^2+11x-6=\left(7x-3\right)\left(x+2\right)$

$\frac{2\left(7x-3\right)\left(x+2\right)}{7x-3}$

$\mathrm{Eliminamos \ termino \ comun \ 7x-3:}$

Solución

$\boxed{2\left(\text{x}+2\right)}$

Saludos...