Question

a)216y³+108y²+18y+1

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Answer 1

RESPUESTA:

$216y^3+108y^2+18y+1$

$\left(6y+1\right)\left(36y^2+12y+1\right)$

Factorizamos :)

$=\left(6y+1\right)\left(6y+1\right)\left(6y+1\right)$

$\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:aaa=a^3$

$\left(6y+1\right)\left(6y+1\right)\left(6y+1\right)=\left(6y+1\right)^3$

$RPTA = \left(6y+1\right)^3$

【ツ】亗 CORONA 亗