Question

Que volumen ocupan 45 g de gas metano a 27ºC y a 800torr?

Answer 1

Respuesta:

Mm CH4 = 16 g/mol

T = 27 + 273 = 300 K

m = 45 g

MOLES= masa / Mm

moles = 45 g / 16 g/mol = 2.813 mol

P = 800 torr

760 torr ------  1 atm

800 torr ------      x

x = 1.0526 atm

R = 0.0821 (mol x atm/ L x mol)

P x V = n x R x T

V = n x R x T

     ````````````

         P

V = 2.813 mol x 0.0821 (mol x atm/ L x mol) x 300 K

     ``````````````````````````````````````````````````````````````````

                            1.0526 atm

V = 65.82 L

Explicación: