Question

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Answer 1

Respuesta:

Explicación paso a paso:

a). $Area\ del\ trapecio = \frac{(base\ menor+base\ mayor)}{2} *altura$

base menor = $\sqrt{450} = \sqrt{9*50} = \sqrt{9*25*2}= 15\sqrt{2}$

base mayor = $\sqrt{50} = \sqrt{25*2} = 5\sqrt{2}$

altura = $\sqrt{150} = \sqrt{3*50} = \sqrt{3*25*2} = 5\sqrt{6}$

A = (15$\sqrt{2}$+5$\sqrt{2}$)/2*5$\sqrt{6}$

A = 10$\sqrt{2}$*5*$\sqrt{2}$*$\sqrt{3}$

A = 100$\sqrt{3}$

b). se multiplica y divide por la conjugada de $\sqrt{11} -\sqrt{6}$

osea $\sqrt{11} +\sqrt{6}$

$\frac{5\sqrt{2} }{\sqrt{11} -\sqrt{6} } *\frac{\sqrt{11} +\sqrt{6}}{\sqrt{11} +\sqrt{6}}$

$\frac{5\sqrt{2}(\sqrt{11} -\sqrt{6} )}{(\sqrt{11})^2-(\sqrt{6})^2}$

$\frac{5(\sqrt{11*2} -\sqrt{6*2})}{11-6}$

$\sqrt{22}$ - 2$\sqrt{3}$

c). 7$\sqrt{450}$  - 4$\sqrt{320}$ + 3$\sqrt{80}$ - 5$\sqrt{500}$

7$\sqrt{225*2}$  - 4$\sqrt{64*5}$ + 3$\sqrt{16*5}$ - 5$\sqrt{100*5}$

7*15$\sqrt{2}$  - 4*8$\sqrt{5}$ + 3*4$\sqrt{5}$ - 5*10$\sqrt{5}$

105$\sqrt{2}$  - 32$\sqrt{5}$ + 12$\sqrt{5}$ - 50$\sqrt{5}$

105$\sqrt{2}$  - 70$\sqrt{5}$