Question

$\sqrt[5]{32} - \sqrt[3]{ - 27} + \sqrt[4]{1} + \sqrt{64}$
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Answer 1

Respuesta:

$\sqrt[5] {32} - \sqrt[3] {- 27} + \sqrt[4]{1} + \sqrt{64 } = \\ 2 + 3 + 1 + 8 = 14$