Question

porfavor ayuda!!!!!!!!!!!!!
(2/5)^3 (2/5)^4 (2/5)^(-5)=
ⅇ^7+ⅇ^(-7)=
(-0,8)^(-6) (-0,8)^3 (0,8)^5=
[(2π)^2 ]^2=

Answer 1

1. Problema

$( \frac{2}{5} )^{3} ( \frac{2}{5} ) ^{4} ( \frac{2}{5} ) ^{5}$

$( \frac{2}{5} ) ^{3 \: + \: 4 \: + \: 5}$

$\boxed{ \bold{( \frac{2}{5} ) ^{12} }}$

2. Problema

${e}^{7} \: + \: {e}^{ - 7}$

$\boxed{ \bold{ {e}^{7} \: + \: \frac{1}{ {e}^{7} } }}$

3. Problema

$( - 0.8) ^{ - 6} ( - 0.8) ^{3} (0.8) ^{5}$

$0.8 ^{ - 6} \: \times \: ( - 0.8 ^{3} ) \: \times \: 0.8 ^{5}$

$- 0.8 ^{2}$

$\boxed{ \bold{- 0.64}}$

4. Problema

$((2\pi) ^{2} ) ^{2}$

$(2\pi) ^{4}$

$\boxed{ \bold{2\pi ^{4} }}$

Besitos OvO