Question

hola, me ayudan?
es urgente pls

a) √100+3³+169:13+³√64×14⁰-2⁴ =

b) √144+3⁴:3 =

c) ³√64+10²:5-(7-2)+2³ = d) (5+2.3)+4²:8-6×1 =

e) 8²:4²+√121:9⁰+(36-15×2)-³√27-2³ =

(y si pueden dejar las cuentas se los agradecería mucho)​

Answer 1

a)$\sqrt{100}+3^3+\frac{169}{13}+\sqrt[3]{64}\times \:14^0\left(-2\right)^4$

$14^0=1$

$=\sqrt{100}+3^3+\frac{169}{13}+\left(-2\right)^4\times \:1\times \sqrt[3]{64}$

$\sqrt{100}=10$

$\frac{169}{13}=13$

$\sqrt[3]{64}\times 1\times(-2)^{4} =2^{4} \times4$

$=10+3^3+13+2^4\times \:4$

$10+13=23$

$=2^4\times \:4+3^3+23$

$2^4\times \:4=64$

$3^3=27$

$=64+27+23$

$64+27+23=114$

$=114$

b) $\sqrt{144}+\frac{3^4}{3}$

$\sqrt{144}=12$

$\frac{3^4}{3}=3^{3}$

$=12+3^3$

$3^3=27$

$=12+27$

$12+27=39$

$=39$

c) $\sqrt[3]{64}+\frac{10^2}{5}-\left(7-2\right)+2^3$

$\sqrt[3]{64}=4$

$\frac{10^2}{5}=2^{5} \times5$

$\left(7-2\right)=-5$

$=4+2^2\cdot \:5-5+2^3$

$4-5=-1$

$=2^3+2^2\cdot \:5-1$

$2^3=8$

$2^2\cdot \:5=20$

$=8+20-1$

$8+20-1=27$

$=27$

d) $\frac{\left(5+2.3\right)+4^2}{8-6\times \:1}$

$=\frac{5+2.3+4^2}{8-6\times \:1}$

$5+2.3+4^2=23.3$

$=\frac{23.3}{8-6\times \:1}$

$8-6\times \:1=2$

$=\frac{23.3}{2}$

$\frac{23.3}{2}=11.65$

$=11.65$

e) $\frac{8^2}{4^2}+\frac{\sqrt{121}}{9^0}+\left(36-15\times \:2\right)\sqrt[3]{27}-2^3$

$9^0=1$

$=\frac{8^2}{4^2}+\frac{\sqrt{121}}{1}+\sqrt[3]{27}\left(36-15\times \:2\right)-2^3$

$\frac{8^2}{4^2}=2^{2}$

$\frac{\sqrt{121}}{1}=11$

$\left(36-15\times \:2\right) \sqrt[3]{27}=18$

$=2^2+11+18-2^3$

$11+18=29$

$=2^2+29-2^3$

$2^2=4$

$=4+29-2^3$

$2^3=8$

$=4+29-8$

$4+29-8=25$

$=25$

$Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)$