Question

Y= 3 cos 2x :)))))) porfa

Answer 1

$y \: = \: 3cos(2x)$

$y' \: = \: \frac{d}{dx} (3cos(2x))$

$y' \: = \: 3 \: \times \: \frac{d}{dx} (cos(2x))$

$y' \: = \: 3 \: \times \: \frac{d}{dg} (cos(g)) \: \times \: \frac{d}{dx} (2x)$

$y' \: = \: 3 \: \times \: ( - sin(g) \: \times \: \frac{d}{dx} (2x))$

$y' \: = \: 3 \: \times \: ( - sin(2x) \: \times \: 2)$

$\boxed{ \bold{y' \: = \: - 6sin(2x)}}$

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