Question

1. (√3 - √2)²
2. (1 + √2) (3 + √2)
3. (3+√2) (3 - √2)

Alguien que me Ayude? De nuevo v:

Answer 1

$1. \:\left(\sqrt{3}\:-\:\sqrt{2}\right)^2$
Aplicar la siguiente regla: $\left(a-b\right)^2=a^2-2ab+b^2$
$=\:\left(\sqrt{3}\right)^2-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^2$
$=3-2 \sqrt{6}+2$
$=5-2 \sqrt{6}$

$2. \left(1\:+\:\sqrt{2}\right)\:\left(3\:+\:\sqrt{2}\right)\:$
Utilizar: $\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$
$=\:1\cdot \:3+1\cdot \sqrt{2}+\sqrt{2}\cdot \:3+\sqrt{2}\sqrt{2}$
$=3+ \sqrt{2}+3 \sqrt{2}+2$
$=4 \sqrt{2}+5$

$3. \left(3+\sqrt{2}\right)\:\left(3\:-\:\sqrt{2}\right)$
$Usar: \left(a+b\right)\left(a-b\right)=a^2-b^2$
$=3^2-\left(\sqrt{2}\right)^2$
$=9-2$
$=7$