Question

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Answer 1

Respuesta:

$\frac{\sqrt[5]{32} *6^{2} +\sqrt{400}}{10-2^{3}}$  $=$ $\frac{\sqrt[5]{2^{5}}*36+\sqrt{20^{2}}}{10-8} =$$\frac{2*36+20}{2}=\frac{72+20}{2}=\frac{92}{2}=46$