Question

si a=1/2; b= 1/3 (-2a-3b)+(7a+5b)-(-3a-b)=

Answer 1

Respuesta:

5

Explicación paso a paso:

a=1/2, b=1/3

(-2a-3b)+(7a+5b)-(-3a-b) = (-2(1/2)-3(1/3))+(7(1/2)+5(1/3))-(-3(1/2)-(1/3)) = (-(2/2)-(3/3))+((7/2)+(5/3))-(-(3/2)-(1/3)) = (-(1/1)-(1/1))+((21/6)+(10/6))-(-(9/6)-(2/6)) = (-1-1)+(31/6)-(-(11/6)) = -2+(31/6)-(-(11/6)) = -(12/6)+(42/6) = 30/6 = 15/3 = 5/1 =5