ayudaaaaaaaaaaaaaaaaaaaaaaaa alguien modedores :(
Adjuntos:
![](https://es-static.z-dn.net/files/dc9/1a8c55635e495934d04cb69badfe0a64.jpg)
Anónimo:
" Moderadores "
Respuestas
Respuesta dada por:
3
Fracciones equivalentes , significa que multiplicando el numerador y el denominador por un mismo numero natural , se cumplirá la equivalencia .
A)![\frac{2}{12} = \frac{1}{6}--mitad,de,cada,uno \frac{2}{12} = \frac{1}{6}--mitad,de,cada,uno](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B12%7D+%3D+%5Cfrac%7B1%7D%7B6%7D--mitad%2Cde%2Ccada%2Cuno)
B)![\frac{1}{3} = \frac{2}{6} = \frac{4}{12} \frac{1}{3} = \frac{2}{6} = \frac{4}{12}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B3%7D+%3D+%5Cfrac%7B2%7D%7B6%7D+%3D+%5Cfrac%7B4%7D%7B12%7D)
C)![\frac{1}{2} = \frac{2}{4} = \frac{5}{10} \frac{1}{2} = \frac{2}{4} = \frac{5}{10}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2%7D+%3D+%5Cfrac%7B2%7D%7B4%7D+%3D+%5Cfrac%7B5%7D%7B10%7D+)
D)![\frac{1}{4} = \frac{2}{8} = \frac{4}{16} \frac{1}{4} = \frac{2}{8} = \frac{4}{16}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B4%7D+%3D+%5Cfrac%7B2%7D%7B8%7D+%3D+%5Cfrac%7B4%7D%7B16%7D+)
E)![\frac{2}{6} = \frac{4}{12} = \frac{1}{3} \frac{2}{6} = \frac{4}{12} = \frac{1}{3}](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B6%7D+%3D+%5Cfrac%7B4%7D%7B12%7D+%3D+%5Cfrac%7B1%7D%7B3%7D+)
Suma y resta de fracciones equivalentes
A)![\frac{1}{2} + \frac{6}{12} = \frac{1}{2}+ \frac{1}{2} = \frac{2+2}{4}= \frac{4}{4}=1 \frac{1}{2} + \frac{6}{12} = \frac{1}{2}+ \frac{1}{2} = \frac{2+2}{4}= \frac{4}{4}=1](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2%7D+%2B+%5Cfrac%7B6%7D%7B12%7D+%3D+%5Cfrac%7B1%7D%7B2%7D%2B+%5Cfrac%7B1%7D%7B2%7D++%3D+%5Cfrac%7B2%2B2%7D%7B4%7D%3D+%5Cfrac%7B4%7D%7B4%7D%3D1++)
B)![\frac{1}{2} - \frac{1}{12} = \frac{12-2}{24} = \frac{10}{24} = \frac{5}{12} \frac{1}{2} - \frac{1}{12} = \frac{12-2}{24} = \frac{10}{24} = \frac{5}{12}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2%7D+-+%5Cfrac%7B1%7D%7B12%7D+%3D+%5Cfrac%7B12-2%7D%7B24%7D+%3D+%5Cfrac%7B10%7D%7B24%7D+%3D+%5Cfrac%7B5%7D%7B12%7D+)
C)![\frac{5}{12} - \frac{2}{6} = \frac{5}{12}- \frac{1}{3} = \frac{15-12}{36} = \frac{3}{36} = \frac{1}{12} \frac{5}{12} - \frac{2}{6} = \frac{5}{12}- \frac{1}{3} = \frac{15-12}{36} = \frac{3}{36} = \frac{1}{12}](https://tex.z-dn.net/?f=+%5Cfrac%7B5%7D%7B12%7D+-+%5Cfrac%7B2%7D%7B6%7D+%3D+%5Cfrac%7B5%7D%7B12%7D-+%5Cfrac%7B1%7D%7B3%7D+%3D+%5Cfrac%7B15-12%7D%7B36%7D+%3D+%5Cfrac%7B3%7D%7B36%7D+%3D+%5Cfrac%7B1%7D%7B12%7D+)
D)![\frac{5}{12} - \frac{1}{4} = \frac{20-12}{48} = \frac{8}{48} = \frac{1}{6} \frac{5}{12} - \frac{1}{4} = \frac{20-12}{48} = \frac{8}{48} = \frac{1}{6}](https://tex.z-dn.net/?f=+%5Cfrac%7B5%7D%7B12%7D+-+%5Cfrac%7B1%7D%7B4%7D+%3D+%5Cfrac%7B20-12%7D%7B48%7D+%3D+%5Cfrac%7B8%7D%7B48%7D+%3D+%5Cfrac%7B1%7D%7B6%7D+)
E)![\frac{1}{3} + \frac{4}{12} = \frac{1}{3} + \frac{1}{3} = \frac{3+3}{9} = \frac{6}{9} \frac{1}{3} + \frac{4}{12} = \frac{1}{3} + \frac{1}{3} = \frac{3+3}{9} = \frac{6}{9}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B3%7D+%2B+%5Cfrac%7B4%7D%7B12%7D+%3D+%5Cfrac%7B1%7D%7B3%7D+%2B+%5Cfrac%7B1%7D%7B3%7D+%3D+%5Cfrac%7B3%2B3%7D%7B9%7D+%3D+%5Cfrac%7B6%7D%7B9%7D+)
F)![\frac{6}{12} - \frac{1}{3}= \frac{6}{12}- \frac{1}{3}= \frac{18-12}{36}= \frac{6}{36}= \frac{1}{6} \frac{6}{12} - \frac{1}{3}= \frac{6}{12}- \frac{1}{3}= \frac{18-12}{36}= \frac{6}{36}= \frac{1}{6}](https://tex.z-dn.net/?f=+%5Cfrac%7B6%7D%7B12%7D+-+%5Cfrac%7B1%7D%7B3%7D%3D+%5Cfrac%7B6%7D%7B12%7D-+%5Cfrac%7B1%7D%7B3%7D%3D+%5Cfrac%7B18-12%7D%7B36%7D%3D+%5Cfrac%7B6%7D%7B36%7D%3D+%5Cfrac%7B1%7D%7B6%7D++)
G)![\frac{3}{12} - \frac{1}{6}= \frac{3}{12}- \frac{1}{6}= \frac{18-12}{72}= \frac{6}{72}= \frac{1}{12} \frac{3}{12} - \frac{1}{6}= \frac{3}{12}- \frac{1}{6}= \frac{18-12}{72}= \frac{6}{72}= \frac{1}{12}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B12%7D+-+%5Cfrac%7B1%7D%7B6%7D%3D+%5Cfrac%7B3%7D%7B12%7D-+%5Cfrac%7B1%7D%7B6%7D%3D+%5Cfrac%7B18-12%7D%7B72%7D%3D+%5Cfrac%7B6%7D%7B72%7D%3D+%5Cfrac%7B1%7D%7B12%7D+)
H)![\frac{1}{4} + \frac{2}{6} + \frac{4}{12} = (\frac{1}{4} + \frac{1}{3}) + \frac{1}{3} = \frac{3+4}{12}+ \frac{1}{3} = \frac{7}{12}+ \frac{1}{3} = \frac{21+12}{36} = \frac{33}{36} = \frac{11}{12} \\ \\ \frac{11}{12} --resultado \frac{1}{4} + \frac{2}{6} + \frac{4}{12} = (\frac{1}{4} + \frac{1}{3}) + \frac{1}{3} = \frac{3+4}{12}+ \frac{1}{3} = \frac{7}{12}+ \frac{1}{3} = \frac{21+12}{36} = \frac{33}{36} = \frac{11}{12} \\ \\ \frac{11}{12} --resultado](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B4%7D+%2B+%5Cfrac%7B2%7D%7B6%7D+%2B+%5Cfrac%7B4%7D%7B12%7D+%3D+%28%5Cfrac%7B1%7D%7B4%7D+%2B+%5Cfrac%7B1%7D%7B3%7D%29+%2B+%5Cfrac%7B1%7D%7B3%7D+%3D+%5Cfrac%7B3%2B4%7D%7B12%7D%2B+%5Cfrac%7B1%7D%7B3%7D++%3D+%5Cfrac%7B7%7D%7B12%7D%2B+%5Cfrac%7B1%7D%7B3%7D+%3D+%5Cfrac%7B21%2B12%7D%7B36%7D+%3D+%5Cfrac%7B33%7D%7B36%7D+%3D+%5Cfrac%7B11%7D%7B12%7D+%5C%5C+%5C%5C+++%5Cfrac%7B11%7D%7B12%7D+--resultado)
Resuelve el siguiente problema , datos : 1/2 , 1/4 , 3/8 , 9/16
Sumemos : 1/2 + 1/4 y 3/8 + 9/16 luego que se de el resultado sumamos
dichos resultados
![\frac{1}{2} + \frac{1}{4} = \frac{4+2}{8} = \frac{6}{8}= \frac{3}{4} \frac{1}{2} + \frac{1}{4} = \frac{4+2}{8} = \frac{6}{8}= \frac{3}{4}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2%7D+%2B+%5Cfrac%7B1%7D%7B4%7D+%3D+%5Cfrac%7B4%2B2%7D%7B8%7D+%3D+%5Cfrac%7B6%7D%7B8%7D%3D+%5Cfrac%7B3%7D%7B4%7D++)
![\frac{3}{8} + \frac{9}{16} = \frac{48+72}{128} = \frac{120}{128} = \frac{15}{16} \frac{3}{8} + \frac{9}{16} = \frac{48+72}{128} = \frac{120}{128} = \frac{15}{16}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B8%7D+%2B+%5Cfrac%7B9%7D%7B16%7D+%3D+%5Cfrac%7B48%2B72%7D%7B128%7D+%3D+%5Cfrac%7B120%7D%7B128%7D+%3D+%5Cfrac%7B15%7D%7B16%7D+)
Ahora sumamos y saldrá la fracción disponible de tela
![\frac{3}{4} + \frac{15}{16} = \frac{48+60}{64} = \frac{108}{64} = \frac{27}{16}=(1 \frac{11}{16}) -tela,disponible\ le\ sobraria\ tela \frac{3}{4} + \frac{15}{16} = \frac{48+60}{64} = \frac{108}{64} = \frac{27}{16}=(1 \frac{11}{16}) -tela,disponible\ le\ sobraria\ tela](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B4%7D+%2B+%5Cfrac%7B15%7D%7B16%7D+%3D+%5Cfrac%7B48%2B60%7D%7B64%7D+%3D+%5Cfrac%7B108%7D%7B64%7D+%3D+%5Cfrac%7B27%7D%7B16%7D%3D%281+%5Cfrac%7B11%7D%7B16%7D%29++-tela%2Cdisponible%5C+le%5C+sobraria%5C+tela)
No pongas el paréntesis , solo lo hice para que sepas que esa es la fracción .
Saludos desde Venezuela , espero te sirva , disculpa la tardanza
A)
B)
C)
D)
E)
Suma y resta de fracciones equivalentes
A)
B)
C)
D)
E)
F)
G)
H)
Resuelve el siguiente problema , datos : 1/2 , 1/4 , 3/8 , 9/16
Sumemos : 1/2 + 1/4 y 3/8 + 9/16 luego que se de el resultado sumamos
dichos resultados
Ahora sumamos y saldrá la fracción disponible de tela
No pongas el paréntesis , solo lo hice para que sepas que esa es la fracción .
Saludos desde Venezuela , espero te sirva , disculpa la tardanza
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