Question

Hola, me podrían ayudar con estos ejercicios porfavor
$(4pq {3} + 3pq{2}) {3}$
$(0.3a - 5.6b{2} c) {3}$
$( \frac{3}{2} xy - \frac{1}{3}yz) {3}$

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Answer 1

Explicación paso a paso:

Binomio al cubo:  

(a ± b)³ = a³ ± 3a²b + 3ab² ± b³

(4pq³  +3pq²)³ = (4pq³)³ +3⋅(3pq²)  (4pq³)²  +3⋅(3pq²)²  (4pq³)   +(3pq² )³

(4pq³  +3pq²)³ = 64p³q⁹+144p³q⁸ +108p³q⁷ +27p³q⁶

(0.3a-5.6b² c)³ = (3/10a)³-3⋅(3/10a²)  (28/5b² c)²  +3⋅(3/10a)²  (28/5b² c)  -(28/5b² c )³

(0.3a+5.6b² c)³ = 0.027a³ - 1.512a²b²c + 28.224ab⁴c² - 175.616b⁶c³

(3/2xy - 1/3yz)³ = (3/2xy)³ -3⋅(3/2xy)  (1/3yz)²  +3⋅(3/2xy)²  (1/3yz)   -(1/3yz)³

(3/2xy - 1/3yz)³ = 27/8x³y³ - 9/4y³x²+ 1/2y³xz² -1/27y³z³