Question

1. 3+(x+1)/2=(x+1)/6
2. (x-8) a la 2 = (x-10) a la 2 +8
3. (x-1)/2 - (x-2)/3 - (x-3)/4 = (x-5)/5
AYUDENME XFA

Answer 1

Respuesta:

3+(x+1)/2 = (x+1)/6 ; m.c.m(2,6) = 6

6(3)+6((x+1)/2) = 6((x+1)/6)

18+3(x+1) = x+1

18+3x+3 = x+1

21+3x = x+1

3x-x = 1-21

2x = -20

2x/2 = -20/2

x = -10

(x-8)² = (x-10)²+8

x²-16x+64 = (x²-20x+100)+8

x²-16x+64 = x²-20x+(100+8)

x²-16x+64 = x²-20x+108

(1-1)x²-16x+64 = -20x+108

-16x+64 = -20x+108

-16x+20x = 108-64

4x = 44

4x/4 = 44/4

x = 11

(x-1)/2-(x-2)/3-(x-3)/4 = (x-5)/5 ; m.c.m(2,3,4,5) = 60

60((x-1)/2)-60((x-2)/3)-60((x-3)/4) = 60((x-5)/5)

30(x-1)-20(x-2)-15(x-3) = 12(x-5)

30x-30-20x+40-15x+45 = 12x-60

(30-20-15)x+(-30+40+45) = 12x-60

(10-15)x+(10+45) = 12x-60

-5x+55 = 12x-60

-5x+55-12x = 12x-60-12x

(-5-12)x+55 = -60

-17x+55 = -60

-17x+55-55 = -60-55

-17x = -115

-17x/-1 = -115/-1

17x = 115

17x/17 = 115/17

x = 115/17

Explicación paso a paso: