Question

El MCM de:
a = x2 - 4
B = x3 + 8
C= x2 + 4x + 4

Ayuden plis​

Answer 1

Explicación paso a paso:

${x}^{2} - 4 = (x + 2)(x - 2) \\ {x}^{3} + 8 = (x + 2)( {x}^{2} - 2x + 4) \\ {x}^{2} + 4x + 4 = ( {x + 2)}^{2} \\ el \: mcm \: es \: ( {x + 2)}^{2} (x - 2)( {x}^{2} - 2x + 4)$