Question

Por favor me ayudan rapido

Answer 1

a) $m^{ \frac{1}{3}} = \sqrt[3]{m}$

b) $a^{\frac{1}{2}} = \sqrt{a}$

c) $(2X^{2}Y^{3})^{\frac{1}{4}} = \sqrt[4]{2X^{2}Y^{3}}$

d) $(2a^{2}b^{3}) ^{- \frac{1}{3} }= \frac{1}{ \sqrt[3]{2a^{2}b^{3}}}$

e) $18^{\frac{2}{3}} =\sqrt[3]{18^{2}} = \sqrt[3]{324}$

f) $d^{\frac{5}{4}} = \sqrt[5]{d^{4}}$

g) $13^{ \frac{1}{2} } = \sqrt{13}$

h) $(5X^{3}Y^{4}Z^{2})^{-\frac{1}{6} }= \frac{1}{ \sqrt[6]{5X^{3}Y^{4}Z^{2}} }$

i) $(2a - 3b)^{ \frac{1}{3}} = \sqrt[3]{(2a - 3b)}$

j)  $(48m^{3})^{ \frac{2}{3}} = \sqrt[3]{(48m^{3})^{2}} = \sqrt[3]{[(6*8)(m^{3})]^{2}}$

$\sqrt[3]{[(6*8)(m^{3})]^{2}} = \sqrt[3]{[36*64*m^{6}]} = 4m^{2} \sqrt[3]{36}$