Question

resolver el sistema de ecuaciones x-4y+z=0
4x-y+6z=0
x-y+3z=0​

Answer 1

Respuesta:

x = 0, y = 0, z = 0

Explicación paso a paso:

x-4y+z=0.....(x-4) (1)

4x-y+6z=0 (2)

x-y+3z=0 (3)(x-1)

-4x + 16y - 4z = 0 x - 4y + z = 0

4x - y + 6z = 0 -x + y - 3z = 0

15y +2z = 0....(x1) (4) 15y +2z = 0

-3y - 2z = 0....(x5) (5) -15y - 10z = 0

-8z = 0 => z = 0 y = 0 x = 0

RPTA:

x = 0, y = 0, z = 0