Question

Resolver la siguiente ecuación diferencial

y' + 2y = 0

dy/dx + 2y = 0

Answer 1

dy/dx + 2y = 0

dy/dx = -2y

(1/y)dy = (-2)dx

∫(1/y)dy = ∫(-2)dx

㏑(y) = -2x + a

y = k e⁻²ˣ  

donde k = eᵃ