Question

1.......4(a + 5)(a − 3)

2.... ..(x²+ 1)(x² - 1)(x² + 1)

.3...m(m-4)(m-6)(3m +2) d) 3x(x²-2x+1)(x - 1)(x + 1)

4...... (x-3)(x + 4)(x - 5)(x + 1)



por fa me ayudan a resolverlos ​

Answer 1

Respuesta:

si no me equivoco son polinomios y monomios​ espero haberte ayudado

$4\left(a+5\right)\left(a-3\right)\\\\=4\left(a^2+2a-15\right)\\\\=4a^2+4\cdot \:2a+4\left(-15\right)\\\\=4a^2+8a-60$

$\left(x^2+1\right)\left(x^2-1\right)\left(x^2+1\right)\\\\=\left(x^2-1\right)\left(x^2+1\right)^{1+1}\\\\=\left(x^2-1\right)\left(x^2+1\right)^2$

$m\left(m-4\right)\left(m-6\right)\left(3m+2\right)\\\\=m\left(m^2-10m+24\right)\left(3m+2\right)\\\\=3m^2m^2+3m^2\left(-10m\right)+3m^2\cdot \:24+2mm^2+2m\left(-10m\right)+2m\cdot \:24\\\\=3m^4-28m^3+52m^2+48m$

$3x\left(x^2-2x+1\right)\left(x-1\right)\left(x+1\right)\\\\=3x\left(x^2-2x+1\right)\left(x^2-1\right)\\\\=\left(3x^3-3x\right)\left(x^2-2x+1\right)\\\\=3x^3x^2+3x^3\left(-2x\right)+3x^3\cdot \:1-3xx^2-3x\left(-2x\right)-3x\cdot \:1\\\\=3x^5-6x^4+6x^2-3x$

$\left(x-3\right)\left(x+4\right)\left(x-5\right)\left(x+1\right)\\\\=\left(x^2+x-12\right)\left(x^2-4x-5\right)\\\\=x^2x^2+x^2\left(-4x\right)+x^2\left(-5\right)+xx^2+x\left(-4x\right)+x\left(-5\right)-12x^2-12\left(-4x\right)-12\left(-5\right)\\\\=x^4-3x^3-21x^2+43x+60$