Question

Composición porcentual de mgfe2 fluoruro de magneso

Answer 1

Mm MgF2

Mg = 1 x 24.3 = 24.3 g/mol
  F = 2 x 18.99 = 37.98 g/mol
````````````````````````````````
           Mm = 62.28 g/mol

Magnesio

62.28 g ----- 100 %
24.3 g -----  x

 x = 39.01 %

Flúor

62.28 g ----- 100 %
37.98 g -----    x

 x = 60.98 %