Question

2×+3(-×2^2-1)=-{3×^2+2(×-1)-3(×+3)}

Answer 1

2X + 3(-X² - 1) = -3[3X² + 2(X - 1) - 3(X + 3)]

2X - 3X² - 3 = -3[3X² + 2X - 2 - 3X - 9]

2X - 3X² - 3 = -3[3X² - X - 11]

2X - 3X² - 3 = -9X² + 3X + 33

2X - 3X² - 3 + 9X² - 3X - 33 = 0

6X² - X - 36 = 0

Donde: a = 6; b = -1;  c = -36

$X=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$X=\frac{-(-1)\pm \sqrt{(-1)^2-4(6)(-36)}}{2(6)}$

$X=\frac{1\pm \sqrt{1-4(6)(-36)}}{2(6)}$

$X=\frac{1\pm \sqrt{1+864}}{2(6)}$

$X=\frac{1\pm \sqrt{865}}{12}$

X1 = [1 + √865]/12: X1 ≈ 2.5342402

X2 = [1 - √865]/12: X2 ≈ -2.3675735