Question

Me pueden ayudar pliss

Answer 1

Respuesta:

Explicación paso a paso:

$\sqrt{x-8}=2\\x-8=2^{2} \\x-8=4\\x=4+8\\x=12$

$5-\sqrt{3x+1} =0\\(-1) -\sqrt{3x+1}=-5 (-1)\\\sqrt{3x+1}=5\\3x+1=5^{2} \\3x+1=25\\3x=25-1\\3x=24\\x=\frac{24}{3}\\x=8$

$\sqrt{5x-19} -\sqrt{5x} =1\\\sqrt{5x-19} =1+\sqrt{5x}\\5x-19=(1+\sqrt{5x})^{2} \\5x-19=1^{2} +2\sqrt{5x} +(\sqrt{5x})^{2} \\5x-19=1+2\sqrt{5x}+5x\\5x-5x=1+2\sqrt{5x}+19\\0=20+2\sqrt{5x}\\-20=2\sqrt{5x}\\\sqrt{5x}=\frac{-20}{2} \\\sqrt{5x}=-10\\5x=(-10)^{2} \\5x=100\\x=\frac{100}{5} \\x=20$

Espero te sirva.... жDaya Princeж