Question

(2x-8)(2x+8)=(2x-8)2​

Answer 1

(2x-8)(2x+8)=(2x-8)2

4x² - 64 = 4x + 16

4x²- 64 - 4x - 16 = 0

4x² - 80 - 4x = 0

x² - 20 - x = 0

x² - x - 20 = 0

x² - 4x - 5x - 20 = 0

x × (x + 4) - 5 (x + 4) = 0

(x+4) (x-5) = 0

x+4=0

x-5=0

x= -4

x= 5

x¹ = -4

x² = 5