Question

(2-1/5)^2/(3-2/9)^(-1) ÷(6/7*5/4-2/7÷1/2)^3/((1/2-1/3*1/4÷1/2) )-5 1/7=
me ayudan es urgente porfa :(

Answer 1

Respuesta:

$\frac{\left(2-\frac{1}{5}\right)^2}{\left(3-\frac{2}{9}\right)^{\left(-1\right)}}\div \frac{\left(\frac{6}{7}\times \frac{5}{4}-\frac{\frac{2}{7}}{\frac{1}{2}}\right)^3}{\left(\left(\frac{1}{2}-\frac{1}{3}\times \frac{\frac{1}{4}}{\frac{1}{2}}\right)\right)}-5\frac{1}{7}$

$=\frac{\left(2-\frac{1}{5}\right)^2}{\left(3-\frac{2}{9}\right)^{\left(-1\right)}}\times \frac{\left(\left(\frac{1}{2}-\frac{1}{3}\times \frac{\frac{1}{4}}{\frac{1}{2}}\right)\right)}{\left(\frac{6}{7}\times \frac{5}{4}-\frac{\frac{2}{7}}{\frac{1}{2}}\right)^3}-\frac{36}{7}$

$=24-\frac{36}{7}\\\\=\frac{24\times \:7}{7}-\frac{36}{7}\\\\=\frac{24\times \:7-36}{7}\\\\=\frac{132}{7}\\\\=18\frac{6}{7}$