Question

((2^{4})^{2})^{-3} x (2^{2})^{2^{2})^{2}

Answer 1

Debes tener en cuenta 

$(a ^{n} ) ^{m} = a ^{n*m}$

$a ^{-n} = \frac{1}{a ^{n} }$

$\frac{a ^{n} }{a ^{m} } = a ^{n-m}$

Aplicamos
$(( 2^{4} ) ^{2} ) ^{-3} = (2^{8} ) ^{-3} = 2^{-24} = \frac{1}{2 ^{24} }$

$(((2 ^{2} ) ^{2} ) ^{2} ) ^{2} =( (2 ^{4} ) ^{2} ) ^{2} =(2 ^{8} ) ^{2} =2 ^{16}$

multiplicamos
$\frac{1}{2 ^{24} } * 2^{16} = \frac{2 ^{16} }{2 ^{24} } =2 ^{16-24} = 2^{-8} = \frac{1}{2 ^{8} }$

Answer 2

Respuesta:

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Explicación paso a paso: