Question

calcula los siguientes porcentajes carbono hidrogeno y oxigeno en metanol

Answer 1

metanol = CH3OH

Mm = 32 g/mol

C: 1 x 12 = 12 g/mol
H: 4 x 1 = 4 g/mol
O: 1 x 16 = 16 g/mol
``````````````````````````````````
     Mm = 32 g/mol

CARBONO:

32 g ---- 100 %
12 g ----    x

  x = 37.5 %

HIdROGENO:

32 g --- 100 %
4 g -----      x

   x = 12.5 %

OXIGENO

32 g ---- 100  %
16 g ----      x
 
       x = 50 %


 

Answer 2

Respuesta:

metanol = CH3OH

Mm = 32 g/mol

C: 1 x 12 = 12 g/mol

H: 4 x 1 = 4 g/mol

O: 1 x 16 = 16 g/mol

``````````````````````````````````

    Mm = 32 g/mol

CARBONO:

32 g ---- 100 %

12 g ----    x

 x = 37.5 %

HIdROGENO:

32 g --- 100 %

4 g -----      x

  x = 12.5 %

OXIGENO

32 g ---- 100  %

16 g ----      x

 

      x = 50 %

Explicación:

espero que te ayude